What is the Period of y = sin3x? We know that for a function sin bx, the period is 2π/|b| which implies the period of sin3x is 2π/3.
1 Answer. Nghi N. So, the period of sin 3x is 2π3.
∣sin3x∣ sinx has period 2π
The period of the function can be calculated using 2π|b| 2 π | b | . Replace b b with 3 3 in the formula for period. The absolute value is the distance between a number and zero. The distance between 0 0 and 3 3 is 3 3 .
Thus sin^3(x/2) is periodic with periodicity of 4 pi/3.
This implies, 2π is a period of sin3x+cos3x.
The Sin3x formula in terms of sinx is given by, sin3x = 3 sinx – 4 sin3x. This sin3x formula can be written as sine three x (sin3x) is equal to the 3 sin x – 4 sin3x. Now, we will derive the sin3x trigonometric formula using the angle addition trigonometric identity.
So the period of sin2x is (2π)/2 = π which implies the value of sin2x repeats after every π radians.
The period for function y = A sin(Bx + C) and y = A cos(Bx + C) is 2π/|B| radians. Frequency is defined as the number of cycles completed in one second. If the period of a function is denoted by P and f be its frequency, then –f =1/ P.
the period of sin5x is 2π/5.
So period is : 22π=π
Period of sinx is 2π.
Constant functions are periodic functions with no fundamental period.