What Is the Iupac Name of Cof6 3?

FAQs Jackson Bowman August 5, 2022

Hexafluorocobalt(3-) | CoF6-3 – PubChem.

What is the structure of CoF6 3?

According to VBT, the form of [CoF6]-3 is:

According to VBT, the form of [CoF6]< sup>3 is octahedral.

What is the oxidation number of Co in CoF6 3?

The coordination number of [CoF6]3 is 6. The oxidation state of Co in this complex is +3< /b> with electronic configuration 3d6 and complex is formed by sp3d2 suggesting that there are six orbitals involved. Therefore, the coordination number of Co is 6.

Why CoF6 3 is high spin?

Fluorine ion is a weak ligand. It cannot cause 3D electron pairing. As a result, the Co3+ ion undergoes sp3d2 hybridization. Complex formation involves outer shell d orbitals, resulting in a high-spin complex.

What is the hybridization of CoF6 3?

Hybridization is sp3d2 and shape is octahedral.

What is the correct electron configuration of central metal atom in CoF6 3?

Therefore, [CoF6]3 sp3d2 > hybridizes and has an octahedral shape. (ii) The atomic number of Ni is 28 and its electronic valence shell configuration is 3d84s2.

What is the magnetic character of CoF6 3?

In the [CoF6]3− complex, the oxidation number of Co is +3. The external electronic configuration of the Co3+ ion is 3d6. It can also be written as t2g4eg2. Thus there are 4 unpaired electrons, 2 in the t2g level and 2 in the eg level.

Why is CoF6 3 paramagnetic?

The electronic configuration of Co3+ is 3d 6 4s 0 . The unpaired electrons can be calculated as it is a strong field ligand, hence pairing of electrons takes place. Hence the complex has no unpaired electrons. a [CoF6 ]3− is paramagnetic because it contains four unpaired electrons.

What is the Colour of CoF6 3?

The color of the cobalt complexes changes from green in [CoF6]3- to yellow in [Co(NH3)6] 3+ and orange in [Co(CN)6]3- .

What is crystal field theory How does this theory account for the fact that CoF6 3 is paramagnetic but Co NH3 6 3+ is diamagnetic though both are octahedral?

In Co has an oxidation state of +3. So Co has 6 valence electrons. Because F is a weak field ligand, it cannot pair. So it has an unpaired electron and is paramagnetic.

Which of these statements about CoF6 3 is true?

1 answer. Correct option (c) [Co(CN) 6] 3 has no unpaired electrons and is in low spin Configuration. Since CN is a strong field ligand, all electrons will be paired and the complex will be a low-spin complex.

Which is more stable CoF6?

[Co(ox)3]3- is more stable than [CoF6]3 – since oxalate is a bidentate ligand, it forms a chelated ring compound by occupying all coordination sites, which is more stable than the normal compound containing a monodentate ligand such as F-.

Which of the following complex is diamagnetic CoF6 3?

In [CoF6]3, unlike F, Co has four unpaired electrons cause d orbitals, while in the case of [Co(C2O4)3]3, C2O4 causes pairing of unpaired electrons in d–orbitals and thus there is no unpaired electron, hence it is diamagnetic in nature.

Is CoF6 3 an outer orbital complex?

II. [Co(C2O4)3]3− is diamagnetic while [CoF6]3− is paramagnetic. III. Both are outer orbital complexes.

What is hybridisation of CoF6 3 Co 27 give its shape and magnetic properties?

The central Co atom is sp3d2 hybridized. It forms an octahedral complex with paramagnetic behavior due to the presence of 4 unpaired electrons. It forms outer orbitals or high-spin or spin-free complexes since it uses outer 4d orbitals in sp3d2 hybridization.

What is valence bond theory explain the formation of CoF6 3 According to this theory?

Six hybrid orbitals of Co3+ overlap with filled orbitals of F forming 6 coordinative bonds followed by an octahedral one geometry lend complex. It’s an outer complex. Since the complex has 4 unpaired electrons, it is paramagnetic. = 4.9 B.M.



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